Page number: Correction

29: The values of the constant B for Si and Ge are reversed in the caption of fig. 2.4.

97: Fig. 3.78 - The polarity of V_{C2} should be reversed in order
to agree with the output voltage waveform.

162: Prob. 4.59 - The gate of the lower FET should be connected to its drain.

173: Eq. (5.13) - The equation for i_{B} should have "exp"
in the last term: [exp(v_{BC}/V_{T}) -1]

brackets299: Prob. 7.41 - Y + ... should be Y = ...

262: Eq. 7.34 V_{IH} = V_{TNS} + 2v_{O} = ...

299: Prob. 7.41 - Y + ... should be Y = ...

310: Line between Eq. (8.4) and (8.5) - ... and v_{DS} = v_{O}.

360: Row 0 - A_{2}, A_{1} and A_{0} should each be
individually complemented; Row 1 - A_{2} and A_{1} be
individually complemented

402: Eq. 10.34 and 10.35 - v_{OH} an v_{OL} should be V_{OH}
and V_{OL}

409: Last line should be = -1.03 V

436: Near bottom: i_{B2} = i_{B1}, not (b_{R}+1)i_{B}, since the
Schottky diode bypasses the base current around the collector-base junction.

437: Fig. 10.72 - B_{1} should be i_{B1}, since i_{B2}
= i_{B1}.

459: Footnote 2: Common IF frequencies include 262 kHz, 455 kHz, 10.7 MHz, 21.4 MHz, 30 MHz, 45 MHz, 60 MHz, 160 MHz.

578: Prob. 12.99 - Calculate the sensitivity of w_{o} with respect
to C_{2} rather than Q.

586: Next to last line: (V_{GS} = 3.5 V)

589: Third answer to second exercise should be i_{c}(t) = -0.26 sin
2000pt mA

609: Eq. 13.66 " = i_{D}" should be removed in the
equation for y_{22}

615: Eq. (13.92) - I_{G} = - I_{SG}

681: The value of R_{th} sybstituted in the C-G voltage gain
expression should be 1.71 kW, not 18 kW.

698: Eq. (14.119) - V_{TH} should be V_{TN}

701: Three lines below Eq. (14.126) - Fig. 14.39(a) should be Fig. 14.42(a)

741: Text just above Fig. 15.13 - " ... reduced by a factor of 3."

745: The second equals sign in Eq. (15.65) should be removed.

749: Eq. (15.84) - eliminate "A_{cd} =" It should only
read A_{cc} = ...

Eq. (15.85) - A_{cd} should
be A_{cc}

_{ } The text below Eq.
(15.85) should read - "... the common-mode gain is determined.... supply
voltages, A_{cc} = 0.5."

750: Top of page - "stage characterized by Eq. (12.79), CMRR is defined
in Eq. (12.83) as"

Eq. (15.88) - CMRR =|(A_{dd}/2)/A_{cc}|
= ...

757: Eq. (15.110) - A_{cc} =(v_{oc}/v_{ic}) = -g_{m}R_{D}/..

Eq. (15.112) - CMRR =|(A_{dd}/2)/A_{cc}|
= ...

788: Eq. (15.194) - The factor of two should be in the numerator, not the
denominator. This error propagates into Eq. (15.195)

in which the answer should be 2.49
mA/V^{2}. In Eq. (15.196), the result should be 5.00 V, and in
Eq. (15.197), R_{3} = 250 kW

which
gives R_{4} = 500 kW.

799: Prob. 15.63 - K_{n} should be K_{p}

820: Eq. (16.23) - h_{11} = 1/(g_{m1}+g_{pi1}+g_{o1}+g_{pi2})
which is approximately equal to 1/g_{m1}

821: Fig. 16.12 should include resistor r_{o1} across the input
port.

840: The polarity of the source attached to v_{2} in Fig. 16.38
should be reversed.

847: Eq. (16.102) The output resistance of the Darlington should be 2r_{o7}/3
which changes the value of A_{V2} to u_{f7}/5.

847: Eq. (16.102) The denominator of Eq. (16.103) then should be 21.7 and
the gain 4.15 x 10^{5}.

909: Eq. (17.31) - R_{4} should be R_{3}

912: Eq. (17.35) - R_{2} should be R_{S}

914: Example 17.3 - R_{3S} = 22.7 W,
C_{3} = 3.50 mF

943: Fig. 17.56 - R_{G} = 243 kW

951: Next to last paragraph - Reference to Fig. 17.66(b) should be Fig. 17.65(b) on page 952.

952, 953, 955: Figures 17.65-17.68 - M1 should be an NMOS depletion-mode MOSFET.

978: Problems 17.41 & 17.42 - Use V_{CC} = +12 V.

980: Problem 17.66 - Use R_{L} = 100 kohms.

997: Middle of page in B: y_{22} is found with v_{1} = 0.

998: A = -119 kW. b = **-**10^{-5} S. The numerator of
the calculation of A_{TR} below Fig. 18.17 is missing a minus sign as
is the answer. The answer should be -54.4 kW.

1011: Table 18.2 - The values of r_{o} should be 155 kW and 64.8 kW

1102: Numerator of Eq. (18.123) should be 2 x 10^{24}.

1033: Eq. 18.143 - The second sGC_{3} term should be sg_{m}C_{GD}.

1045: Problem 18.33 - Use C_{1} = C_{2} = 1 mF.

1098: First answer to Prob. 2.7 should be negative.

1102: Prob. 10.103 - Y = A+B+C; 0 V, **-0.90 V**; 0 V, **-0.45 V**

1105: Prob. 14.47 - ... C-B or **C-G**...;
Prob. 14.53 - -u_{f}**v _{s}**,