Problem 2.13, Page 11: The velocity should be 10^{7} cm/s yielding
16,000 A/cm^{2}.

Prob. 2.25, Page 13: u_{p}p = 8.32 x 10** ^{18}**/V-cm-s
and the problem only has one solution - the first bold entry in the table
with u

Prob. 3.20, Page 22: V_{T} = 0.0264 V

Prob. 3.34, Page 26: The load line should intersect the v_{D}
axis at **+5** V.

Prob. 3.41, Page 29: Q-Point for CVD model should be (40.0 mA,
**0.6
V**).

Prob. 3.54(a), Page 33: The denominator of the I_{Z} expression
should be 50. The answer is correct.

Prob. 7.16, Page 110: I_{DS} = 33 uA

Prob. 7.36, Page 114: (W/L)_{L} = 1/2.06

Prob. 13.33(b), Page 286: C_{3} is a bypass capacitor, and R_{1}
should be replaced by a short circuit in both schematics.

Prob. 14.12, Page 319: The expression for A_{I} should be multiplied
by an additional current division factor at the collector of 8.2kW/(8.2kW+100kW)
so that A_{I} = -4.62.

Prob. 14.21, Page 322: A typo occurred in the last line. It should be
**v _{be}**
= 0.985

Prob. 15.31: Note in the (b) part that v_{1} = v_{2}
= 5 V exceeeds the common-mode input range for the amplifier. The
input transistors are saturated.

One possible modification would be to change V_{CC} to +18
V.

Prob. 15.54: R_{SS} appearing in the denominator of the last
equation should be I_{DS}.

Prob. 15.69: The dc half-circuit should use an ideal current source symbol.

Prob. 15.79, Page 380: The expression for A_{v1} is incorrect.

Prob. 15.91, Page 386: R_{D} = 3.83 kohms which yields A_{dm}
= 528

Prob. 15.93, Page 387: V_{CE} = V_{CC} - V_{EB3}
- (-V_{BE2}) = 5.00 V

Prob. 15.95, Page 388: R_{L} should be 5 kohms which yields
emitter follower gain = 0.980 and A_{dm} = 249

Prob. 16.19, Page 413: The last line R_{OUT2} should be R_{OUT3}.

Prob. 16.48, Page 422: The last equality should be I_{C6} =
5.42 uA.

Prob. 16.61, Page 428: I_{C2} = **200** uA-... ; At bottom
, V_{BE3} = V_{EB4} = ...

Prob. 16.64: Table values for V_{DS7} and V_{DS8} should
be 7.25 V and 2.75 V respectively.

Prob. 16.75: First line - I_{C44} should be I_{C14}.
Note that two transistors are accidentally labeled as Q_{6}.

Prob. 17.7, Page 453: A division symbol should follow the (1/2p)
term in the f_{H} expression

Prob. 17.23, Page. 461: The value of C_{p}
in the first row should be 0.773 pF

Prob. 17.69, Page 482: The wrong value of capacitance was used in the calculations. It should be 7.5 pF yielding answers of 10.6 MHz and 33.3 V/ms.

Prob. 17.75, Page 484: The value of r_{o} is calculated incorrectly
and affects the rest of the answers. r_{o} = 6.99 kohm, A_{V}
= -41.1, BW = 7.74 MHz, Q = 2.91

Prob 18.26, Page 507: The positive directions for v_{1} and
i_{o} are both backwards. This error cancels in the evaluation
of A. However, v_{o} = -5000 i_{o}, so A_{v}
= -1.

THE FOLLOWING PROBLEMS WERE ADDED TO THE SECOND PRINTING AND SOLUTIONS ARE INCLUDED IN THE SOLUTIONS MANUAL.

**CHAPTER 12**

12.134 Two diodes are added to the circuit in Fig. P12.131 to convert it to a monostable multivibrator similar to the circuit in Fig. 12.76, and the power supplies are changed to ±10V. What are the pulse width and recovery time of the monostable circuit?

12.135 Design a monostable multivibrator to have a pulse width of 10 us and a recovery time of 5 us. Use the circuit in Fig. 12.76 with ±5 V.

Problem Correction

12.114 (a) What is the output voltage at the end of one clock cycle
of the SC integrator in Fig. 12.53 if C_{1} = 1 pF, C_{2}
= 0.2 pF, v_{s} = 1 V, and there is a stray capacitance C_{S}
= 0.1 pF between each end of capacitor C_{1} and ground. What are
the gain and gain error of this circuit? (b) Repeat for the integrator
in Fig. 12.57.

**CHAPTER 17**

Light bulb: 17.85 Change the two capacitor values in the circuit in Fig. P17.84(a) to give the same center frequency as in Fig. P17.84(b). What are the Q and mid-band gain for the new circuit?

SPICE: 17.86 (a) Simulate the circuit in Prob. 17.84(a) and compare the results to the hand calculations in Prob. 17.84. (b) Simulate the circuit in Prob. 17.84(b) and compare the results to the hand calculations in Prob. 17.84. (c) Simulate the circuit in Prob. 17.85 and compare the results to the hand calculations in Prob. 17.85.

*17.87 (a) Derive an expression for the input admittance of the common-emitter
circuit in Fig. 17.21 and show that the input capacitance and input resistance
can be represented by the expressions below for wC_{u}R_{L}
<< 1.

C_{in} = C_{pi} + C_{u} (1+g_{m}R_{L})

R_{in} = r_{pi} ||{R_{L}/[(1+g_{m}R_{L})(wC_{u}R_{L})^{2}]}

(b) A MOSFET has C_{GS} = 6 pF, C_{GD} = 2 pF, g_{m}
= 5 mS and R_{L} = 10 kohms. What are the values of C_{in}
and R_{in} at a frequency of 5 MHz?