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Motion Relative to a Rotating Frame
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The visualization below shows a (red) hockey puck sliding across a (blue) frictionless turn table. The same motion is viewed in two different camera frames. Since there are no forces acting on the puck, its acceleration relative to the inertial XY frame is zero. Additionally, the turn table is not accelerating and is rotating at a constant rate. Therefore, the acceleration of the puck relative to the rotating xy frame is:
relative acceleration = - ( centripetal acceleration + Coriolis acceleration )
This relative acceleration is apparent in the camera view rotating with the xy frame. To an observor in this frame, the puck appears to deflect to the right.
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(The velocity of the puck and the angular velocity of the table happen to be such that the puck travels the radius of the table in the time the table rotates one quarter turn.) |